RoboShark: Difference between revisions
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This wiki will contain information about my Bachelor Final Project. | This wiki will contain information about my Bachelor Final Project. | ||
== 1. Introduction == | |||
Lorem ipsum dolor sit amet, consectetur adipiscing elit. Sed vestibulum convallis justo, at vulputate risus vulputate et. Fusce non velit vitae quam dapibus ullamcorper. Lorem ipsum dolor sit amet, consectetur adipiscing elit. Integer tincidunt rhoncus massa, ac fermentum risus sollicitudin vitae. Nulla vitae orci sit amet erat feugiat malesuada a a leo. Vestibulum sem ligula, aliquet eu blandit eget, gravida vel eros. Maecenas pharetra congue massa at sodales. Aenean condimentum, tellus id sagittis malesuada, nibh nunc feugiat orci, dictum consectetur lacus neque sit amet sapien. Class aptent taciti sociosqu ad litora torquent per conubia nostra, per inceptos himenaeos. Morbi adipiscing arcu ullamcorper purus commodo ac elementum augue hendrerit. Pellentesque volutpat enim sed tortor consequat in iaculis ante pharetra. | |||
Cras tristique semper urna, id bibendum sapien lobortis id. Donec nisi eros, mattis sed fermentum sit amet, accumsan a libero. Sed sapien mauris, varius a placerat eget, ultricies at ligula. Mauris dignissim ornare pulvinar. Nulla facilisi. Cras nec interdum est. Integer quis accumsan sapien. Quisque vehicula, metus id accumsan fringilla, mauris mauris adipiscing nisi, eget molestie velit mi et lorem. Maecenas augue massa, pulvinar sed adipiscing at, posuere eget dolor. Nam ligula odio, ultricies sit amet mollis sit amet, gravida at erat. Donec pellentesque, nisl at rutrum posuere, nibh urna tincidunt turpis, imperdiet gravida massa nisl nec nunc. Ut in felis ut quam posuere mattis. Nam quis tortor quis arcu scelerisque tincidunt. Vivamus non euismod purus. | |||
== 2. Pre-Design Research == | |||
=== 2.1 Helium === | |||
The shark will float through the air by using helium. To determine how much helium is needed to make the shark neutrally buoyant Archimedes’ principle is be used. This principle states that any object, wholly or partially immersed in a fluid, is buoyed up by a force equal to the weight of the fluid displaced by the object. The upward lift is defined in equation X.X. <br> | |||
''EQUATION''<br> | |||
The whole shark will have a certain weight on which a gravitational force is applied. The total amount of gravitational force is given in equation X.X.<br> | |||
''EQUATION'' <br> | |||
The whole shark will have a certain weight on which a gravitational force is applied. The total amount of gravitational force is given in equation X.X.<br> | |||
''F_z=M∙g=(M_(shark)+M_(helium) )∙g= (M_(shark)+ρ_(helium)∙V)∙g ''<BR> | |||
To make the shark neutrally buoyant the force from the lift has to be equal to the force applied by gravity, which is displayed in equation X.X. If the upward lift equals the gravitational force, no net force in vertical direction will be present. <br> | |||
''F_a=F_z'' <br> | |||
Substituting the terms in equation X.X. with the terms from equation X.X. and X.X., a relation between the mass of the shark and the amount of helium needed can be derived. This relation is given in equation X.X.<br> | |||
''ρ_air∙g∙V= (M_(shark)+ρ_(helium)∙V)∙g <br> | |||
M_(shark)=(ρ_air-ρ_(helium) )∙V<br> | |||
ρ_air=P/(R∙T) (kg/m^3 )'' <br> | |||
If the assumption is made that the temperature is equal to 293K and the pressure is 1 bar, the density of air is equal to 1,204 kg per cubic meter. At the same conditions the density of helium is 0,1787 kg per cubic meter. Using these values for the densities of air and helium, 1 cubic meter of helium can make 1 kg neutrally buoyant. | |||
Using relation from equation X.X, the amount of helium needed to make the shark neutrally buoyant can be determined. |
Revision as of 11:09, 7 July 2011
Project by Twan Haazen
Supervisor Rob Janssen
This wiki will contain information about my Bachelor Final Project.
1. Introduction
Lorem ipsum dolor sit amet, consectetur adipiscing elit. Sed vestibulum convallis justo, at vulputate risus vulputate et. Fusce non velit vitae quam dapibus ullamcorper. Lorem ipsum dolor sit amet, consectetur adipiscing elit. Integer tincidunt rhoncus massa, ac fermentum risus sollicitudin vitae. Nulla vitae orci sit amet erat feugiat malesuada a a leo. Vestibulum sem ligula, aliquet eu blandit eget, gravida vel eros. Maecenas pharetra congue massa at sodales. Aenean condimentum, tellus id sagittis malesuada, nibh nunc feugiat orci, dictum consectetur lacus neque sit amet sapien. Class aptent taciti sociosqu ad litora torquent per conubia nostra, per inceptos himenaeos. Morbi adipiscing arcu ullamcorper purus commodo ac elementum augue hendrerit. Pellentesque volutpat enim sed tortor consequat in iaculis ante pharetra. Cras tristique semper urna, id bibendum sapien lobortis id. Donec nisi eros, mattis sed fermentum sit amet, accumsan a libero. Sed sapien mauris, varius a placerat eget, ultricies at ligula. Mauris dignissim ornare pulvinar. Nulla facilisi. Cras nec interdum est. Integer quis accumsan sapien. Quisque vehicula, metus id accumsan fringilla, mauris mauris adipiscing nisi, eget molestie velit mi et lorem. Maecenas augue massa, pulvinar sed adipiscing at, posuere eget dolor. Nam ligula odio, ultricies sit amet mollis sit amet, gravida at erat. Donec pellentesque, nisl at rutrum posuere, nibh urna tincidunt turpis, imperdiet gravida massa nisl nec nunc. Ut in felis ut quam posuere mattis. Nam quis tortor quis arcu scelerisque tincidunt. Vivamus non euismod purus.
2. Pre-Design Research
2.1 Helium
The shark will float through the air by using helium. To determine how much helium is needed to make the shark neutrally buoyant Archimedes’ principle is be used. This principle states that any object, wholly or partially immersed in a fluid, is buoyed up by a force equal to the weight of the fluid displaced by the object. The upward lift is defined in equation X.X.
EQUATION
The whole shark will have a certain weight on which a gravitational force is applied. The total amount of gravitational force is given in equation X.X.
EQUATION
The whole shark will have a certain weight on which a gravitational force is applied. The total amount of gravitational force is given in equation X.X.
F_z=M∙g=(M_(shark)+M_(helium) )∙g= (M_(shark)+ρ_(helium)∙V)∙g
To make the shark neutrally buoyant the force from the lift has to be equal to the force applied by gravity, which is displayed in equation X.X. If the upward lift equals the gravitational force, no net force in vertical direction will be present.
F_a=F_z
Substituting the terms in equation X.X. with the terms from equation X.X. and X.X., a relation between the mass of the shark and the amount of helium needed can be derived. This relation is given in equation X.X.
ρ_air∙g∙V= (M_(shark)+ρ_(helium)∙V)∙g
M_(shark)=(ρ_air-ρ_(helium) )∙V
ρ_air=P/(R∙T) (kg/m^3 )
If the assumption is made that the temperature is equal to 293K and the pressure is 1 bar, the density of air is equal to 1,204 kg per cubic meter. At the same conditions the density of helium is 0,1787 kg per cubic meter. Using these values for the densities of air and helium, 1 cubic meter of helium can make 1 kg neutrally buoyant.
Using relation from equation X.X, the amount of helium needed to make the shark neutrally buoyant can be determined.